How do you solve $x^2 + 8x – 48 = 0$ by completing the square?

Question

18156 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-31T08:53:23

$x=-12$
$x=4$

$x^2+8x-48=0$
or
$x^2+12x-4x-48=0$
or
$x(x+12)-4(x+12)=0$
or
$(x+12)(x-4)=0$
or
$x+12=0$
or
$x=-12$
or
$x-4=0$
or
$x=4$

How do you solve x^2 + 8x – 48 = 0x^2 + 8x – 48 = 0 by completing the square?