How do you solve x2lnx=ln186?

1 Answer
Apr 15, 2016

There is no real solution.

Explanation:

The equation can rearranged to the form
ln(18x)=x2+6

So, 18x=ex2+6=e6sx2=403.43ex2, nearly.#.

Draw the graphs for y = 18 x and y=403.43ex2.

The first is a straight line through the origin with slope 18, running from the fourth to the first quadrant.

The second is exponential and asymptotic to y = 0, and is raising from y-axis at x=, in the second quadrant, entering the first quadrant through A(0, 403.43). At A, the slope is 403.43, never to meet y = 18 x.
So, there is no solution. .