How do you solve #x+2/x=3#? Algebra Polynomials and Factoring Zero Product Principle 1 Answer Milena Feb 8, 2017 #x=1# or #x=2# Explanation: #x+ 2/x = 3# #2/x = 3-x# #2 = x(3-x)# #2= 3x-x^2# #x^2-3x+2=0# #(x-1)(x-2)=0# #x-1 = 0# or #x-2 = 0# #x=1# or #x=2# Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 1532 views around the world You can reuse this answer Creative Commons License