Question

How do you solve `(x-3)(x-5)(x+1)=0`?

Answer 1

`color(blue)(x = 3, 5, -1)`

Explanation:

`(x-3) * (x-5) * (x+1) = 0`

i.e. `x-3 =0 or x-5 = 0 or x+1 = 0`

Case 1 : `x - 3 = 0, color(green)(x = 3)`

Case 2 : `x - 5 = 0, color(green)(x = 5)`

Case 3 : `x + 1 = 0, color(green)(x = -1)`