How do you solve #(x+3)(x-6)=0#? Algebra Polynomials and Factoring Zero Product Principle 1 Answer LM · Mark D. Jun 28, 2018 #x = -3 or x= 6# Explanation: any number multiplied by #0# is #0#. this means that either #x+3# or #x-6# can be #0# for #(x+3)(x-6)# to be #0#. if #x+3 = 0#, then #x = -3# if #x-6 = 0#, then #x = 6# hence, #x# can either be #-3# or #6#. Answer link Related questions What is the Zero Product Principle? How to use the zero product principle to find the value of x? How do you solve the polynomial #10x^3-5x^2=0#? Can you apply the zero product property in the problem #(x+6)+(3x-1)=0#? How do you solve the polynomial #24x^2-4x=0#? How do you use the zero product property to solve #(x-5)(2x+7)(3x-4)=0#? How do you factor and solve #b^2-\frac{5}{3b}=0#? Why does the zero product property work? How do you solve #(x - 12)(5x - 13) = 0#? How do you solve #(2u+7)(3u-1)=0#? See all questions in Zero Product Principle Impact of this question 11324 views around the world You can reuse this answer Creative Commons License