How do you solve #-x + 3y =10#, #x+y=2# by graphing and classify the system?
2 Answers
Two unknowns and two equations
Explanation:
Add these equations first:
If
The first equation (GRAPH) graph{(10+x)/3 [-10, 10, -5, 5]}
The second equation (GRAPH) graph{2-x [-10, 10, -5, 5]}
Together: graph{(-x+3y-10)(x+y-2)=0 [-10, 10, -5, 5]}
Se below for solution by (only) graphing
Explanation:
Pick a pair of sample points for the equation
Pick a pair of sample points for the equation
Plot the points for each equation and draw a line through the pair for each:
Read the solution as the intersection point directly from the graph: