How do you solve x=log_12 144x=log12144?

1 Answer
Dec 2, 2015

x=2x=2

Explanation:

Even if there's nothing to "solve", strictly speaking, I assume you simply want to simplify log_{12}(144)log12(144), and it's very simple:

log_{a}(b)=xloga(b)=x means that xx is the exponent that you must give to aa to obtain bb. Namely: a^x=bax=b.

This means that, in your case, log_{12}(144)log12(144) is the exponent that you must give to 1212 to obtain 144144, and since 144=12^2144=122, that exponent is 22. So,

x=log_{12}(144)=2x=log12(144)=2