Question

How do you solve `x=log_36 6`?

Answer 1

Use the change of base formula and basic properties of logs to find:

`x = 1/2`

Explanation:

If `a, b, c > 0` then `log_a b = (log_c b) / (log_c a)`

So:

`log_36 6 = (log 6)/(log 36) = (log 6)/(log 6^2) = (log 6) / (2 log 6) = 1/2`