How do you solve #x-y=-2, 2x+y=8# using graphing?
1 Answer
See a solution process below:
Explanation:
First, we can graph the first line by find two points on the line, plotting them and drawing a line through them:
For
For
graph{(x^2+(y-2)^2-0.125)((x+2)^2+y^2-0.125)(x-y+2)=0 [-20,20,-10,10]}
We can now do the same thing for the second equation:
For
For
graph{(x^2+(y-8)^2-0.125)((x-4)^2+y^2-0.125)(2x+y-8)(x^2+(y-2)^2-0.125)((x+2)^2+y^2-0.125)(x-y+2)=0 [-20,20,-10,10]}
We can now see where the two lines cross:
graph{(2x+y-8)(x-y+2)((x-2)^2+(y-4)^2-0.05)=0 [-5,15,-5,5]}
They cross at