How do you state the degree and leading coefficient of the polynomial function $F (x) = 14 + 13 x^{4} - 6 x - 14 x^{3} - 8 x^{2}$ $F(x) = 14+ 13x^4 - 6x - 14x^3 -8x^2$ ?

Question

How do you state the degree and leading coefficient of the polynomial function $F (x) = 14 + 13 x^{4} - 6 x - 14 x^{3} - 8 x^{2}$ $F(x) = 14+ 13x^4 - 6x - 14x^3 -8x^2$ ?

1 Answer

Impact of this question

7649 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-08-23T00:12:19

The leading coefficient is $13$ $13$
The degree is $4$ $4$

Explanation:

To obtain the leading coefficient it is necessary to rewrite the equation in canonical form, that is with the terms listed in descending order of their $x$ $x$ exponents:

$F (x) = 13 x^{4} - 14 x^{3} - 8 x^{2} - 6 x + 14$ $F(x) = 13x^4-14x^3-8x^2-6x+14$

The leading coefficient is the coefficient of the highest order $x$ $x$ term

The degree is the degree (exponent) of the highest order $x$ $x$ term

Science

Math

Humanities

... and beyond

How do you state the degree and leading coefficient of the polynomial function $F (x) = 14 + 13 x^{4} - 6 x - 14 x^{3} - 8 x^{2}$ $F(x) = 14+ 13x^4 - 6x - 14x^3 -8x^2$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you state the degree and leading coefficient of the polynomial function F(x) = 14+ 13x^4 - 6x - 14x^3 -8x^2F(x)=14+13x4−6x−14x3−8x2F(x) = 14+ 13x^4 - 6x - 14x^3 -8x^2?

1 Answer

Explanation:

Related questions

Impact of this question

How do you state the degree and leading coefficient of the polynomial function $F (x) = 14 + 13 x^{4} - 6 x - 14 x^{3} - 8 x^{2}$ $F(x) = 14+ 13x^4 - 6x - 14x^3 -8x^2$ ?