How do you take the derivative of ${tan}^{2} (3 x)$ $tan^2(3x)$ ?

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Answer 1 · 2018-04-25T11:40:03

$\frac{d}{d x} {tan}^{2} 3 x = 6 tan 3 x {sec}^{2} 3 x$ $d/dxtan^2 3x=6tan3xsec^2 3x$

To find the derivative, we use the chain rule for functions

$d/dx[f(x)]^n=n[f(x)]^(n-1)f'(x)$

So

$d/dxtan^2 3x=2tan3x(3sec^2 3x)=6tanxsec^2 3x$

How do you take the derivative of tan^2(3x)tan2(3x) tan^2(3x)?