Question

How do you take the derivative of `tan^2(4x)`?

Answer 1

`(d[tan^2(4x)])/(dx)=8sec^2(4x)tan(4x)`

Explanation:

Use the chain rule:

`(d[tan^2(4x)])/(dx)=2sec^2(4x).tan(4x)xxd((4x))/dx`

`=2sec^2(4x).tan(4x)xx4`

`=8sec^2(4x)tan(4x)`