How do you take the derivative of ${tan}^{2} (4 x)$ $tan^2(4x)$ ?

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Answer 1 · 2015-07-02T22:07:49

$\frac{d [{tan}^{2} (4 x)]}{d x} = 8 {sec}^{2} (4 x) tan (4 x)$ $(d[tan^2(4x)])/(dx)=8sec^2(4x)tan(4x)$

$\frac{d [{tan}^{2} (4 x)]}{d x} = 2 {sec}^{2} (4 x) . tan (4 x) \times d \frac{(4 x)}{d x}$ $(d[tan^2(4x)])/(dx)=2sec^2(4x).tan(4x)xxd((4x))/dx$

$= 2 {sec}^{2} (4 x) . tan (4 x) \times 4$ $=2sec^2(4x).tan(4x)xx4$

$= 8 {sec}^{2} (4 x) tan (4 x)$ $=8sec^2(4x)tan(4x)$

How do you take the derivative of tan^2(4x)tan2(4x) tan^2(4x)?