How do you take the derivative of ${tan}^{3} (2 x - x^{3})$ $tan^3(2x-x^3)$ ?

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How do you take the derivative of ${tan}^{3} (2 x - x^{3})$ $tan^3(2x-x^3)$ ?

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Answer 1 · 2015-06-03T17:40:04

I would use the Chain Rule deriving the ${()}^{3}$ $()^3$ first, then the $tan$ $tan$ and finally the argument of the $tan$ $tan$ :
$y'=3tan^2(2x-x^3)xx1/(cos^2(2x-x^3))xx(2-3x^2)$

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How do you take the derivative of ${tan}^{3} (2 x - x^{3})$ $tan^3(2x-x^3)$ ?

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How do you take the derivative of ${tan}^{3} (2 x - x^{3})$ $tan^3(2x-x^3)$ ?