How do you take the derivative of ${tan}^{5} (x)$ $tan^5(x)$ ?

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Answer 1 · 2015-06-06T13:35:19

You can try using the Chain Rule, deriving ${()}^{5}$ $()^5$ first and then the $tan$ $tan$ , as:
$y'=5tan^4(x)*1/cos^2(x)$

Where I used to derive:

$x^5=x^n-> nx^(n-1)$
$tan(x) -> 1/cos^2(x)$

How do you take the derivative of tan^5(x)tan5(x) tan^5(x)?