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How do you test the improper integral #int (2x)/(sqrt(x^2+1)) dx# from #(-oo, oo)# and evaluate if possible?

1 Answer

Feb 28, 2017

See below.

Explanation:

#(2x)/(sqrt(x^2+1))# is an odd function so

#int_(-a)^a (2x)/(sqrt(x^2+1)) dx = 0#

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