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How do you test the series #Sigma 1/sqrt(n(n+1))# from n is #[1,oo)# for convergence?

1 Answer

Jan 27, 2017

See below.

Explanation:

#1/(n+1) < 1/sqrt(n(n+1)) < 1/n#

and

#sum 1/n# does not converge

so

#sum 1/sqrt(n(n+1)) # does not converge!

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