How do you use find the zeroes of $f (x) = 4 x^{3} - 4 x$ $f(x)=4x^3-4x$ ?

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How do you use find the zeroes of $f (x) = 4 x^{3} - 4 x$ $f(x)=4x^3-4x$ ?

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Answer 1 · 2016-09-15T09:21:31

$x = 0, x = \pm 1$ $x=0 , x=+-1$

Explanation:

The zeroes of f(x) are the values of x that make f(x) = 0

That is $4 x^{3} - 4 x = 0$ $4x^3-4x=0$

Factorising gives.

$4 x (x^{2} - 1) = 0 \Rightarrow 4 x (x - 1) (x + 1) = 0$ $4x(x^2-1)=0rArr4x(x-1)(x+1)=0$

solving for x.

$\Rightarrow x = 0, x = \pm 1 are the zeroes$ $rArrx=0,x=+-1" are the zeroes"$

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How do you use find the zeroes of $f (x) = 4 x^{3} - 4 x$ $f(x)=4x^3-4x$ ?

1 Answer

Explanation:

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How do you use find the zeroes of $f (x) = 4 x^{3} - 4 x$ $f(x)=4x^3-4x$ ?