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How do you use Heron's formula to determine the area of a triangle with sides of that are 4, 6, and 8 units in length?

1 Answer

Mar 15, 2016

$P = 3 \sqrt{15}$ $P = 3sqrt15$

Explanation:

$s = \frac{a + b + c}{2}$ $s = (a+b+c)/2$

$s = \frac{4 + 6 + 8}{2} = 9$ $s = (4+6+8)/2 = 9$

$P = \sqrt{s (s - a) (s - b) (s - c)}$ $P = sqrt(s(s-a) (s-b)(s-c))$

$P = \sqrt{9 \cdot (9 - 4) (9 - 6) (9 - 8)} = \sqrt{9 \cdot 5 \cdot 3} = 3 \sqrt{15}$ $P = sqrt(9*(9-4)(9-6)(9-8)) = sqrt( 9*5*3 ) = 3sqrt15$

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