How do you use Heron's formula to determine the area of a triangle with sides of that are 6, 4, and 4 units in length?

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How do you use Heron's formula to determine the area of a triangle with sides of that are 6, 4, and 4 units in length?

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Answer 1 · 2016-02-09T14:00:24

Area ≈ 7.94

Explanation:

This is a 2 step process

step 1 : calculate ( half of the perimeter (s) ) of the triangle

step 2 : calculate the area (A)

let a = 6 , b = 4 and c = 4

step 1 : s = $\frac{a + b + c}{2} = \frac{6 + 4 + 4}{2} = \frac{14}{2} = 7$ $(a + b + c )/2 = (6 + 4 + 4 )/2 = 14/2 = 7$

step 2 : A $= \sqrt{s (s - a) (s - b) (s - c)}$ $= sqrt(s(s-a)(s-b)(s-c))$

$= \sqrt{7 (7 - 6) (7 - 4) (7 - 4)}$ $= sqrt(7(7-6)(7-4)(7-4))$

$= \sqrt{7 \times 1 \times 3 \times 3} = \sqrt{63} \approx 7.94$ $= sqrt(7 xx 1 xx 3 xx 3) = sqrt63 ≈ 7.94$

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How do you use Heron's formula to determine the area of a triangle with sides of that are 6, 4, and 4 units in length?

1 Answer

Explanation:

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