How do you use Heron's formula to find the area of a triangle with sides of lengths $3$ , $5$ , and $4$ ?

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Answer 1 · 2016-02-13T21:46:57

Heron's formula states that:
$A=sqrts(s-a)(s-b)(s-c)$

where s is equal to:
$s=(a+b+c)/2$

If a=3. b=5, and c=4, then plugging in the numbers. we get:
$s=(3+5+4)/2=6$

so:
$A=sqrt6(6-3)(6-5)(6-4)=sqrt36$ which can be further simplified to just 6, due to the fact that $sqrt36=6$

How do you use Heron's formula to find the area of a triangle with sides of lengths 3 3 , 5 5 , and 4 4 ?