Question

How do you use Heron's formula to find the area of a triangle with sides of lengths `29`, `25`, and `22`?

Answer 1

≈ 266.71 square units

Explanation:

This is a 2 step process

step 1 : Find half the perimeter ( s ) of the triangle

let a = 29 , b = 25 and c = 22

`rArr s = (a+b+c)/2 = (29+25+22)/2 = 76/2 = 38`

step 2 : Calculate the area (A ) using

`A = sqrt(s(s-a)(s-b)(s-c))`

`= sqrt(38(38-29)(38-25)(38-22))`

`= sqrt(38xx9xx13xx16) ≈ 266.71 " square units"`