How do you use Heron's formula to find the area of a triangle with sides of lengths #12 #, #5 #, and #9 #?

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Answer 1 · 2016-05-15T11:51:43

Area #=4sqrt26" "#square units

Given sides
Let #a=12# and #b=5# and #c=9#

solve half of perimeter #s# first

#s=(a+b+c)/2=(12+5+9)/2=13#

Area #=sqrt (s(s-a)(s-b)(s-c))#

Area #=sqrt (13(13-12)(13-5)(13-9))#

Area #=4sqrt26" "#square units

God bless ....I hope the explanation is useful