How do you use Heron's formula to find the area of a triangle with sides of lengths 12 , 6 , and 11 ?

1 Answer

Area =32.83957217" "square units

Explanation:

let sides a=12 and b=6 and c=11

compute half the perimeter s=(a+b+c)/2

s=(12+6+11)/2=14.5

The Heron's Formula for area of the triangle

Area =sqrt(s(s-a)(s-b)(s-c))

Area =sqrt(14.5(14.5-12)(14.5-6)(14.5-11))

Area =32.83957217" "square units

God bless....I hope the explanation is useful.