Question

How do you use special angles to find the ratios of sin 150 degrees?

Answer 1

`sin(150^o) = 1/2`

Explanation:

`sin(pi-theta) = sin(theta)`

`sin(150^o) = sin(180^o-sin^o) = sin(30^o)`

`30^o` is one of the "special angles" with `sin(30^o)=1/2`

So `sin(150^o) = 1/2`