How do you use the distributive property to factor $10g^2h^2+9gh^2-g^2h$ ?

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Answer 1 · 2017-10-31T22:27:32

We can factor $gh$ out of each term giving:

$(10gh * gh) + (9h * gh) - (g * gh) =>$

$(10gh + 9h - g)gh$

How do you use the distributive property to factor 10g^2h^2+9gh^2-g^2h10g^2h^2+9gh^2-g^2h?