How do you use the distributive property to factor $5 c^{2} v - 15 c^{2} v^{2} + 5 c^{2} v^{3}$ $5c^2v-15c^2v^2+5c^2v^3$ ?

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Answer 1 · 2017-07-26T12:36:02

See a solution process below:

We can rewrite the expression as:

$(5 c^{2} v \cdot 1) - (5 c^{2} v \cdot 3 v) + (5 c^{2} v \cdot v^{2})$ $(5c^2v * 1) - (5c^2v * 3v) + (5c^2v * v^2)$

Now, we can factor out the common term:

$5 c^{2} v (1 - 3 v + v^{2}) \Rightarrow$ $5c^2v(1 - 3v + v^2) =>$

$5 c^{2} v (v^{2} - 3 v + 1)$ $5c^2v(v^2 - 3v + 1)$

How do you use the distributive property to factor 5c^2v-15c^2v^2+5c^2v^35c2v−15c2v2+5c2v35c^2v-15c^2v^2+5c^2v^3?