How do you use the distributive property to factor $5z^2+10z$ ?

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Answer 1 · 2018-03-18T12:49:17

$5z(z+2)$

Notice that both terms have a common factor of $5z$

Divide both terms by $5z$

$5z^2 +10z$

$=5z(z+2)$

With the distributive law, the factor outside is multiplied INTO the bracket.

To factorise the HCF is divided OUT of the bracket.

How do you use the distributive property to factor 5z^2+10z5z^2+10z?