How do you use the law of sines to solve the triangle given A = 104.9°, B = 8.1°, b = 3.1?

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Answer 1 · 2015-07-01T23:34:36

I found for the length of the sides:
$21.3 and 20.3$ $21.3 and 20.3$
and the missing angle of $67°$

From the Law of Sines:
$a/sinA=b/sinB=c/sinC$

in your case:
$a/sin(104.9°)=3.1/sin(8.1°)=c/sinC$

$C=180-104.9-8.1=67°$

Now:

Step 1:

$a/sin(104.9°)=3.1/sin(81°)$
so $a=21.3$

Step 2:

$3.1/sin(8.1°)=c/sin(67°)$
so:
$c=20.3$