How do you use the law of sines to solve the triangle given A = 104.9°, B = 8.1°, b = 3.1?

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Answer 1 · 2015-07-01T23:34:36

I found for the length of the sides:
#21.3 and 20.3#
and the missing angle of #67°#

From the Law of Sines:
#a/sinA=b/sinB=c/sinC#

in your case:
#a/sin(104.9°)=3.1/sin(8.1°)=c/sinC#

#C=180-104.9-8.1=67°#

Now:

Step 1:

#a/sin(104.9°)=3.1/sin(81°)#
so #a=21.3#

Step 2:

#3.1/sin(8.1°)=c/sin(67°)#
so:
#c=20.3#