Question

How do you use the law of sines to solve the triangle given A = 75.1°, B = 37.9°, b = 30?

Answer 1

`C = 180^circ - A - B`

`a = {b sin A}/sin B`

`c = {b sin C}/sin B`

Explanation:

`C = 180^circ - A - B = 180^circ - 75.1^circ - 37.9^circ = 67^circ`

`a/sin A = b/sin B = c/sin C`

`a = b sin A/sin B = 30 { sin 75.1 ^circ }/{ sin 37.9^circ } approx 47.1952`

`c = b sin C/sin B = 30 { sin 67^circ }/{ sin 37.9^circ } approx 44.9549`