How do you use the product to sum formulas to write #6sin45^circcos15^circ# as a sum or difference?

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Answer 1 · 2018-05-11T12:09:49

#6 sin 45 cos 15 =3/2 (sqrt 3+1)#

Formula:

#sin alpha cos beta=1/2 { sin (alpha+beta) +sin (alpha-beta)}#

#alpha=45^0 , beta= 15^0#

# 6 sin 45 cos 15 = 6*1/2 {sin(45+15)+sin(45-15)}# or

# 6 sin 45 cos 15 = 3 (sin 60+sin 30)# or

#6 sin 45 cos 15 =3 (sqrt 3/2+1/2)# or

#6 sin 45 cos 15 =3/2 (sqrt 3+1)# [Ans]