Question

How do you use the special product for squaring binomials to multiply `(1/4t+2 )^2`?

Answer 1

By using

`(a+b)^2=a^2+2ab+b^2`,

we have

`(1/4t+2)^2=(1/4t)^2+2(1/4t)(2)+(2)^2`

`=1/16 t^2+t+4`

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I hope that this was what you meant by "the special product."