How do you write 2x^2+4x-5 into vertex form? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Nghi N. May 13, 2015 (-b/2a) = -4/4 = -1 f(-b/2a) = f(-1) = 2 - 4 - 5 = -7 Factored form: f(x) = 2(x + 1)^2 - 7 Check: Develop f(x) = 2(x^2 + 2x + 1) -5 = 2x^2 + 4x - 5. Correct Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write y+1=-2x^2-x in the vertex form? How do you write the quadratic equation given a=-2 and the vertex (-5, 0)? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation y=-4x^2+20x-24? How do you write y=9x^2+3x-10 in vertex form? What is the vertex of y=-1/2(x-4)^2-7? What is the vertex form of y=x^2-6x+6? See all questions in Vertex Form of a Quadratic Equation Impact of this question 1388 views around the world You can reuse this answer Creative Commons License