How do you write $(3 w^{2} - 8 w - 6) - (4 w^{2} + 4 w - 4)$ $(3w^2-8w-6)-(4w^2+4w-4)$ in standard form?

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Answer 1 · 2017-01-16T18:31:33

$- w^{2} - 12 w - 2$ $-w^2 - 12w - 2$

First, remove all the terms from parenthesis:

$3 w^{2} - 8 w - 6 - 4 w^{2} - 4 w + 4$ $3w^2 - 8w - 6 - 4w^2 - 4w + 4$

Next, group like terms:

$3 w^{2} - 4 w^{2} - 8 w - 4 w - 6 + 4$ $3w^2 - 4w^2 - 8w - 4w - 6 + 4$

Now group like terms:

$(3 - 4) w^{2} + (- 8 - 4) w - 2$ $(3 - 4)w^2 + (-8 - 4)w - 2$

$- 1 w^{2} - 12 w - 2$ $-1w^2 - 12w - 2$

$- w^{2} - 12 w - 2$ $-w^2 - 12w - 2$

How do you write (3w^2-8w-6)-(4w^2+4w-4)(3w2−8w−6)−(4w2+4w−4)(3w^2-8w-6)-(4w^2+4w-4) in standard form?