How do you write a polynomial function given the real zeroes -1, 2, and 3 and coefficient 1? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer Bdub Apr 21, 2016 y=x^3-4x^2+x+6 Explanation: y=(x+1)(x-2)(x-3) y=(x+1)(x^2-5x+6) y=x^3-5x^2+6x+x^2-5x+6 y=x^3-4x^2+x+6 Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of f(x) = 5x^7 − x + 216? What are the zeros of f(x)= −4x^5 + 3? How many times does f(x)= 6x^11 - 3x^5 + 2 intersect the x-axis? What are the real zeros of f(x) = 3x^6 + 1? How do you find the roots for 4x^4-26x^3+50x^2-52x+84=0? What are the intercepts for the graphs of the equation y=(x^2-49)/(7x^4)? See all questions in Zeros Impact of this question 1591 views around the world You can reuse this answer Creative Commons License