How do you write a polynomial function of least degree with integral coefficients that has the given zeroes 4, -1, -3i? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer Vinícius Ferraz May 26, 2017 p(z)=z4−3z3+5z2−27z−36 Explanation: p(z)=(z−4)(z+1)(z−3i)(z+3i) =(z2−3z−4)(z2+9) =z4−3z3−4z2+9z2−27z−36 Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of f(x)=5x7−x+216? What are the zeros of f(x)=−4x5+3? How many times does f(x)=6x11−3x5+2 intersect the x-axis? What are the real zeros of f(x)=3x6+1? How do you find the roots for 4x4−26x3+50x2−52x+84=0? What are the intercepts for the graphs of the equation y=x2−497x4? See all questions in Zeros Impact of this question 2811 views around the world You can reuse this answer Creative Commons License