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How do you write a polynomial function of least degree with integral coefficients that has the given zeros 5/3, 1, -1?

1 Answer

Vinícius Ferraz

May 24, 2017

$p (x) = 3 x^{3} - 5 x^{2} - 3 x + 5$ $p(x) = 3x^3 -5x^2 - 3x + 5$

Explanation:

$(x - \frac{5}{3}) (x - 1) (x + 1) = 0$ $(x - 5/3)(x - 1)(x + 1) = 0$

$(3 x - 5) (x^{2} - 1) = 0$ $(3x - 5)(x^2 - 1) = 0$

$3 x^{3} - 3 x - 5 x^{2} + 5 = 0$ $3x^3 - 3x -5x^2 + 5 = 0$

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