How do you write a polynomial function of minimum degree with real coefficients whose zeros include those listed: 5i and √5?

1 Answer
Nov 8, 2015

f(x)=(x2+25)(x5)=x35x2+25255

or if you want rational coefficients:

g(x)=(x2+25)(x25)=x4+20x2125

Explanation:

If a polynomial has Real coefficients, then any non-Real Complex roots will occur in Complex conjugate pairs. So the roots of our polynomial must include 5i, 5i and 5.

If we allow irrational coefficients then the monic polynomial of lowest degree with these roots is:

f(x)=(x5i)(x+5i)(x5)=(x2+25)(x5)

=x35x2+25255

To have rational coefficient then we also need the irrational conjugate 5 of 5 resulting in:

g(x)=(x5i)(x+5i)(x5)(x+5)=(x2+25)(x25)

=x4+20x2125

Any polynomial with these roots will be a multiple (scalar or polynomial) of f(x) or g(x)