Question

How do you write a polynomial in standard form given the zeros +1, -1 , 3 double root?

Answer 1

The biquadratic equation with roots `1. -1, 3 and 3` is
`x^4-6x^3+8x^2+6x-9=0`

Explanation:

The biquadratic having factors `(x-1), (x+1)(x+3)(x+3)` is

`f(x)=(x^2-1)(x^2-6x+9)=x^4-6x^3+8x^2+6x-9`

So, the equation with roots 1, -1 anmd 3 double root is

`f(x)=(x^2-1)(x^2-6x+9)=x^4-6x^3+8x^2+6x-9`