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How do you write a polynomial in standard form given the zeros x=3,3,3?

1 Answer

Mar 2, 2016

$p (x) = (x - 3) (x - 3) (x - 3) = {(x - 3)}^{3} = x^{3} - 9 x^{2} + 27 x - 27$ $p(x)=(x-3)(x-3)(x-3)=(x-3)^3=x^3-9x^2+27x-27$

Explanation:

x=3,3,3 means $(x - 3) (x - 3) (x - 3) = {(x - 3)}^{3}$ $(x-3)(x-3)(x-3) = (x-3)^3$ then just multiply it out or use pascal's triangle to expand it.

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