How do you write a polynomial in standard form given the zeros x=3i and 3?

1 Answer
Jun 24, 2016

According to what you want, the simplest polynomials are:

x2+(3i3)x33i

x33x2+9x93

x4+6x227

Explanation:

A polynomial of lowest degree with these zeros is:

(x+3i)(x3)=x2+(3i3)x33i

Typically we would be interested in the polynomial having Real coefficients. If so, then any non-Real Complex zeros occur in Complex conjugate pairs. Hence x=3i would also be a zero and the simplest polynomial is:

(x3i)(x+3i)(x3)

=(x2+9)(x3)

=x33x2+9x93

If we also want the polynomial to have rational coefficients, then any irrational zeros of the form a+b occur in radical conjugate pairs. That is, if a+b is a zero then so is ab.

Hence the simplest polynomial with the given zeros and rational coefficients is the quartic:

(x3i)(x+3i)(x3)(x+3)

=(x2+9)(x23)

=x4+6x227