Question

How do you write a polynomial in standard form given zeros 5, -1, -3i, 3i?

Answer 1

`x^4-4x^3+4x^2+36x-45=0`.

Explanation:

The biquadratic equation is

`prod(x-zero)=(x-5)(x+1)(x-3i)(x+3i)=0`

So,`(x^2-4x-5)(x^2+9)=0`, Expanding,
.
`x^4-4x^3+4x^2+36x-45=0`.