How do you write a quadratic function in intercept form whose graph has x intercepts 0, 4 and passes through (-1, 20)?

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How do you write a quadratic function in intercept form whose graph has x intercepts 0, 4 and passes through (-1, 20)?

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Answer 1 · 2017-06-12T12:53:46

$y = 4 x (x - 4)$ $y=4x(x-4)$

Explanation:

$since the x-intercepts are 0 and 4$ $"since the x-intercepts are " 0" and "4$

$then factors are (x - 0) and (x - 4)$ $"then factors are " (x-0)" and " (x-4)$

$\Rightarrow y = a x (x - 4)$ $rArry=ax(x-4)$

$to find a substitute (- 1, 20) into the equation$ $"to find a substitute " (-1,20)" into the equation"$

$20 = a (- 1) (- 5) \Rightarrow a = \frac{20}{5} = 4$ $20=a(-1)(-5)rArra=20/5=4$

$\Rightarrow y = 4 x (x - 4) \leftarrow in intercept form$ $rArry=4x(x-4)larrcolor(red)" in intercept form"$

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How do you write a quadratic function in intercept form whose graph has x intercepts 0, 4 and passes through (-1, 20)?

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