Question

How do you write an equation for a circle with center (3,0) and the radius is 1?

Answer 1

`(x-3)^2+y^2=1`

Explanation:

The standard form of the equation of a circle is.

`color(red)(|bar(ul(color(white)(a/a)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(a/a)|)))`
where (a ,b) are the coordinates of the centre and r, the radius.

here a = 3, b= 0 and r = 1

substitute these values into the equation.

`(x-3)^2+(y-0)^2=1^2`

`rArr(x-3)^2+y^2=1" is the equation of the circle"`