Question

How do you write an equation for a circle with center C(3,-2) and radius 4?

Answer 1

`(x-3)^2 +(y+2)^2 = 16`

Explanation:

The equation of a circle is

`(x-h)^2 +(y-k)^2 = r^2`

Where `(h,k)` are the center of the circle and `r` is the radius

The center is `(3,-2)` and `r = 4`

`(x-3)^2 +(y-(-2))^2 = 4^2`

`(x-3)^2 +(y+2)^2 = 16`