Question

How do you write an equation in point-slope form for the line with the given slope 8/3 and through the given point (-2,-7)?

Answer 1

You have to use the point-slope relationship:
`y-y_0=m(x-x_0)`
where:
`m` is the slope
(`x_0,y_0`) are the coordinates of your point.

So you get:
`y-(-7)=8/3(x-(-2))`
`y+7=(8/3)x+16/3`
`y=(8/3)x-5/3`