Question

How do you write an equation in slope-intercept form for a line with (5,0) and has a slope of -2/3?

Answer 1

Find the y-intercept with the given slope and given point, to find the general equation of `y=(-2/3)x+10/3`

Explanation:

Slope -intercept form is expressed in the form:

`y=mx+b` where `m` is the slope and `b` is the y intercept.

We're given the slope as `-2/3`.

To find `b`, let's fill in the equation with what we know: the slope and a point (an `x` and associated `y` point#):

`0=(-2/3)5+b` (multiply the fraction by 5, then add it to both sides)

`b=10/3`

That give's the final answer as:

`y=(-2/3)x+10/3`