How do you write an equation in standard form for a line which passes through the point (5,2) and has a slope of -7/8?

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Answer 1 · 2015-05-04T16:21:20

Start with standard slope-point form:
#(y-y_1) = m(x-x_1)#
or for the given example with point #(x_1,y_1)(5,2)# and slope #m=-7/8#

#(y-2) = -7/8(x-5)#

#8(y-2) = -7(x-5)#

Converting to standard form: #Ax+By=C#

#7x +8y = 51#