How do you write an equation in standard form given a line that passes through (-2,6), with m=0?

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Answer 1 · 2018-04-21T22:21:12

#y=6#

Any line that has a slope of #0# is a horizontal line; the #y# value stays the same while the #x# value changes.

#y=mx+b rarr# Slope-intercept form of a line where #m# is the slope and #b# is the y-intercept

#y=0x+b rarr# The slope is #0#

Plug in the point #(-2, 6)#

#6=0*-2+b#

#6=0+b#

#b=6#

#y=0x+6 rarr# Anything multiplied by #0# is #0#

#y=0+6#

#y=6#