How do you write an equation in standard form given a line that passes through (-2,6), with m=0?

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Answer 1 · 2018-04-21T22:21:12

$y = 6$ $y=6$

Any line that has a slope of $0$ $0$ is a horizontal line; the $y$ $y$ value stays the same while the $x$ $x$ value changes.

$y = m x + b \to$ $y=mx+b rarr$ Slope-intercept form of a line where $m$ $m$ is the slope and $b$ $b$ is the y-intercept

$y = 0 x + b \to$ $y=0x+b rarr$ The slope is $0$ $0$

Plug in the point $(- 2, 6)$ $(-2, 6)$

$6 = 0 \cdot - 2 + b$ $6=0*-2+b$

$6 = 0 + b$ $6=0+b$

$b = 6$ $b=6$

$y = 0 x + 6 \to$ $y=0x+6 rarr$ Anything multiplied by $0$ $0$ is $0$ $0$

$y = 0 + 6$ $y=0+6$

$y = 6$ $y=6$