How do you write an equation in standard form given point (-2,5) and slope 1?
2 Answers
y = x+7
Explanation:
-
Use the formula y=mx+c
m = gradient of graph
c= y intercept -
Substitute y,m and x in equation to find c
5=1*-2 +c
5=-2+c
7=c -
Replace m and c with numbers found
Therefore equation is y = x + 7
Explanation:
"the equation of a line in "color(blue)"standard form" is.
color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))
"where A is a positive integer and B, C are integers"
"begin by expressing the equation in "color(blue)"point-slope form"
color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))
where m represents the slope and(x_1,y_1)" a point on the line"
"here " m=1" and " (x_1,y_1)=(-2,5)
y-5=1(x-(-2))
rArry-5=x+2larrcolor(red)" in point-slope form"
"subtract y from both sides"
cancel(y)cancel(-y)-5=x+2-y
rArr-5=x+2-y
"subtract 2 from both sides"
-5-2=xcancel(+2)cancel(-2)-y
rArr-7=x-y " or "
x-y=-7larrcolor(red)" in standard form"