How do you write an equation in standard form given point (-2,5) and slope 1?

2 Answers
May 7, 2017

y = x+7

Explanation:

  • Use the formula y=mx+c
    m = gradient of graph
    c= y intercept

  • Substitute y,m and x in equation to find c
    5=1*-2 +c
    5=-2+c
    7=c

  • Replace m and c with numbers found
    Therefore equation is y = x + 7

May 7, 2017

x-y=-7

Explanation:

"the equation of a line in "color(blue)"standard form" is.

color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))

"where A is a positive integer and B, C are integers"

"begin by expressing the equation in "color(blue)"point-slope form"

color(red)(bar(ul(|color(white)(2/2)color(black)(y-y_1=m(x-x_1))color(white)(2/2)|)))
where m represents the slope and (x_1,y_1)" a point on the line"

"here " m=1" and " (x_1,y_1)=(-2,5)

y-5=1(x-(-2))

rArry-5=x+2larrcolor(red)" in point-slope form"

"subtract y from both sides"

cancel(y)cancel(-y)-5=x+2-y

rArr-5=x+2-y

"subtract 2 from both sides"

-5-2=xcancel(+2)cancel(-2)-y

rArr-7=x-y " or "

x-y=-7larrcolor(red)" in standard form"