How do you write an equation in standard form of the circle with the given properties: Center at (−15, 0); $r = \sqrt{14}$ $r = sqrt14$ ?

Question

2329 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-12T01:43:47

General equation of a circle:
${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$ $(x-h)^2+(y-k)^2=r^2$

Center $= (h, k)$ $=(h,k)$

Inserting the values from the problem ...

${(x + 15)}^{2} + {(y)}^{2} = 14$ $(x+15)^2+(y)^2=14$

hope that helped

enter image source here

How do you write an equation in standard form of the circle with the given properties: Center at (−15, 0); r=√14r = sqrt14?